6x^2+4x-4=104

Solution for 6x^2+4x-4=104 equation:

6x^2+4x-4=104

We move all terms to the left:

6x^2+4x-4-(104)=0

We add all the numbers together, and all the variables

6x^2+4x-108=0

a = 6; b = 4; c = -108;
Δ = b2-4ac
Δ = 42-4·6·(-108)
Δ = 2608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2608}=\sqrt{16*163}=\sqrt{16}*\sqrt{163}=4\sqrt{163}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{163}}{2*6}=\frac{-4-4\sqrt{163}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{163}}{2*6}=\frac{-4+4\sqrt{163}}{12}
$